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diff --git a/src/ch04-01-ownership.md b/src/ch04-01-ownership.md
index 020ca2b..de9d336 100644
--- a/src/ch04-01-ownership.md
+++ b/src/ch04-01-ownership.md
@@ -167,7 +167,7 @@ You might say “copy the `String`!” This is both correct and incorrect at the
same time. It does a _shallow_ copy of the `String`. What’s that mean? Well,
let’s take a look at what `String` looks like under the covers:
-
+
A `String` is made up of three parts: a pointer to the memory that holds the
contents of the string, a length, and a capacity. The length is how much memory
@@ -180,11 +180,11 @@ When we assign `s1` to `s2`, the `String` itself is copied, meaning we copy the
pointer, the length, and the capacity. We do not copy the data that the
`String`'s pointer refers to. In other words, it looks like this:
-
+
_Not_ this:
-
+
There’s a problem here. Both data pointers are pointing to the same place. Why
is this a problem? Well, when `s2` goes out of scope, it will free the memory
@@ -240,7 +240,7 @@ also invalidates the first binding, instead of calling this a shallow copy,
it's called a _move_. Here we would read this by saying that `s1` was _moved_
into `s2`. So what actually happens looks like this:
-
+
That solves our problem! With only `s2` valid, when it goes out of scope, it
alone will free the memory, and we’re done.
@@ -279,7 +279,7 @@ println!("{}", s1);
This will work just fine. Remember our diagram from before? In this case,
it _is_ doing this:
-
+
When you see a call to `clone()`, you know that some arbitrary code is being
executed, and that code may be expensive. It’s a visual indicator that something
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