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Smooth out a sentence.

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Ezekiel Smithburg 2016-01-14 01:02:04 -05:00
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src/ownership.md
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@ -227,7 +227,7 @@ Let’s take a step back: the root of the problem is that `s1` and `s2` both
think that they have control of the memory, and therefore, need to free it.
Instead of trying to copy the memory, we could say that `s1` is no longer
valid, and therefore, doesn’t need to free anything. This is in fact the
choice that Rust makes. Check it out what happens when you try to use `s1`
choice that Rust makes. Check out what happens when you try to use `s1`
after `s2` is created:
```rust,ignore