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fix(tree): add c codes
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@ -201,8 +201,8 @@ TreeNode *search(avlTree *tree, int val) {
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TreeNode *cur = tree->root;
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// 循环查找,越过叶结点后跳出
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while (cur != NULL) {
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// 目标结点在 root 的右子树中
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if (cur->val < val) {
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// 目标结点在 root 的右子树中
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cur = cur->right;
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} else if (cur->val > val) {
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// 目标结点在 root 的左子树中
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@ -54,11 +54,15 @@ TreeNode *search(binarySearchTree *bst, int num) {
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// 循环查找,越过叶结点后跳出
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while (cur != NULL) {
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// 目标结点在 root 的右子树中
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if (cur->val < num) cur = cur->right;
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if (cur->val < num) {
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cur = cur->right;
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} else if (cur->val > num) {
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// 目标结点在 root 的左子树中
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else if (cur->val > num) cur = cur->left;
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cur = cur->left;
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} else {
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// 找到目标结点,跳出循环
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else break;
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break;
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}
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}
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// 返回目标结点
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return cur;
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@ -72,17 +76,25 @@ TreeNode *insert(binarySearchTree *bst, int num) {
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// 循环查找,越过叶结点后跳出
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while (cur != NULL) {
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// 找到重复结点,直接返回
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if (cur->val == num) return NULL;
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if (cur->val == num) {
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return NULL;
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}
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pre = cur;
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// 插入位置在 root 的右子树中
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if (cur->val < num) cur = cur->right;
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if (cur->val < num) {
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// 插入位置在 root 的右子树中
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cur = cur->right;
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} else {
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// 插入位置在 root 的左子树中
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else cur = cur->left;
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cur = cur->left;
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}
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}
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// 插入结点 val
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TreeNode *node = newTreeNode(num);
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if (pre->val < num) pre->right = node;
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else pre->left = node;
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if (pre->val < num) {
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pre->right = node;
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} else {
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pre->left = node;
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}
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return node;
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}
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@ -97,6 +109,7 @@ TreeNode *getInOrderNext(TreeNode *root) {
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}
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/* 删除结点 */
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// 由于引入了 stdio.h ,此处无法使用 remove 关键词
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TreeNode *removeNode(binarySearchTree *bst, int num) {
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// 若树为空,直接提前返回
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if (bst->root == NULL) return NULL;
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@ -106,23 +119,31 @@ TreeNode *removeNode(binarySearchTree *bst, int num) {
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// 找到待删除结点,跳出循环
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if (cur->val == num) break;
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pre = cur;
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// 待删除结点在 root 的右子树中
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if (cur->val < num) cur = cur->right;
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if (cur->val < num) {
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// 待删除结点在 root 的右子树中
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cur = cur->right;
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} else {
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// 待删除结点在 root 的左子树中
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else cur = cur->left;
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cur = cur->left;
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}
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}
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// 若无待删除结点,则直接返回
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if (cur == NULL) return NULL;
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// 子结点数量 = 0 or 1
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if (cur == NULL) {
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return NULL;
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}
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// 判断待删除结点是否存在子结点
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if (cur->left == NULL || cur->right == NULL) {
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/* 子结点数量 = 0 or 1 */
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// 当子结点数量 = 0 / 1 时, child = nullptr / 该子结点
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TreeNode *child = cur->left != NULL ? cur->left : cur->right;
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// 删除结点 cur
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if (pre->left == cur) pre->left = child;
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else pre->right = child;
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}
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// 子结点数量 = 2
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else {
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if (pre->left == cur) {
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pre->left = child;
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} else {
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pre->right = child;
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}
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} else {
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/* 子结点数量 = 2 */
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// 获取中序遍历中 cur 的下一个结点
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TreeNode *nex = getInOrderNext(cur->right);
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int tmp = nex->val;
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