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feat: add Swift codes for permutations_problem article (#482)
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@ -59,6 +59,8 @@ let package = Package(
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.executable(name: "preorder_traversal_ii_compact", targets: ["preorder_traversal_ii_compact"]),
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.executable(name: "preorder_traversal_iii_compact", targets: ["preorder_traversal_iii_compact"]),
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.executable(name: "preorder_traversal_iii_template", targets: ["preorder_traversal_iii_template"]),
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.executable(name: "permutations_i", targets: ["permutations_i"]),
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.executable(name: "permutations_ii", targets: ["permutations_ii"]),
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],
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targets: [
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// helper
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@ -118,5 +120,7 @@ let package = Package(
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.executableTarget(name: "preorder_traversal_ii_compact", dependencies: ["utils"], path: "chapter_backtracking", sources: ["preorder_traversal_ii_compact.swift"]),
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.executableTarget(name: "preorder_traversal_iii_compact", dependencies: ["utils"], path: "chapter_backtracking", sources: ["preorder_traversal_iii_compact.swift"]),
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.executableTarget(name: "preorder_traversal_iii_template", dependencies: ["utils"], path: "chapter_backtracking", sources: ["preorder_traversal_iii_template.swift"]),
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.executableTarget(name: "permutations_i", path: "chapter_backtracking", sources: ["permutations_i.swift"]),
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.executableTarget(name: "permutations_ii", path: "chapter_backtracking", sources: ["permutations_ii.swift"]),
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]
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)
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50
codes/swift/chapter_backtracking/permutations_i.swift
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50
codes/swift/chapter_backtracking/permutations_i.swift
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@ -0,0 +1,50 @@
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/**
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* File: permutations_i.swift
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* Created Time: 2023-04-30
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* Author: nuomi1 (nuomi1@qq.com)
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*/
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/* 回溯算法:全排列 I */
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func backtrack(state: inout [Int], choices: [Int], selected: inout [Bool], res: inout [[Int]]) {
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// 当状态长度等于元素数量时,记录解
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if state.count == choices.count {
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res.append(state)
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return
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}
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// 遍历所有选择
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for (i, choice) in choices.enumerated() {
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// 剪枝:不允许重复选择元素 且 不允许重复选择相等元素
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if !selected[i] {
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// 尝试:做出选择,更新状态
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selected[i] = true
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state.append(choice)
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// 进行下一轮选择
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backtrack(state: &state, choices: choices, selected: &selected, res: &res)
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// 回退:撤销选择,恢复到之前的状态
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selected[i] = false
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state.removeLast()
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}
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}
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}
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/* 全排列 I */
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func permutationsI(nums: [Int]) -> [[Int]] {
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var state: [Int] = []
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var selected = Array(repeating: false, count: nums.count)
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var res: [[Int]] = []
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backtrack(state: &state, choices: nums, selected: &selected, res: &res)
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return res
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}
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@main
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enum PermutationsI {
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/* Driver Code */
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static func main() {
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let nums = [1, 2, 3]
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let res = permutationsI(nums: nums)
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print("输入数组 nums = \(nums)")
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print("所有排列 res = \(res)")
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}
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}
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52
codes/swift/chapter_backtracking/permutations_ii.swift
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52
codes/swift/chapter_backtracking/permutations_ii.swift
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@ -0,0 +1,52 @@
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/**
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* File: permutations_ii.swift
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* Created Time: 2023-04-30
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* Author: nuomi1 (nuomi1@qq.com)
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*/
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/* 回溯算法:全排列 II */
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func backtrack(state: inout [Int], choices: [Int], selected: inout [Bool], res: inout [[Int]]) {
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// 当状态长度等于元素数量时,记录解
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if state.count == choices.count {
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res.append(state)
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return
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}
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// 遍历所有选择
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var duplicated: Set<Int> = []
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for (i, choice) in choices.enumerated() {
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// 剪枝:不允许重复选择元素 且 不允许重复选择相等元素
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if !selected[i], !duplicated.contains(choice) {
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// 尝试:做出选择,更新状态
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duplicated.insert(choice) // 记录选择过的元素值
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selected[i] = true
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state.append(choice)
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// 进行下一轮选择
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backtrack(state: &state, choices: choices, selected: &selected, res: &res)
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// 回退:撤销选择,恢复到之前的状态
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selected[i] = false
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state.removeLast()
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}
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}
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}
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/* 全排列 II */
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func permutationsII(nums: [Int]) -> [[Int]] {
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var state: [Int] = []
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var selected = Array(repeating: false, count: nums.count)
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var res: [[Int]] = []
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backtrack(state: &state, choices: nums, selected: &selected, res: &res)
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return res
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}
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@main
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enum PermutationsII {
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/* Driver Code */
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static func main() {
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let nums = [1, 2, 3]
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let res = permutationsII(nums: nums)
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print("输入数组 nums = \(nums)")
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print("所有排列 res = \(res)")
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}
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}
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