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feat: Add javascript and typescript code in chapter_computational_com… (#780)
* feat: Add javascript and typescript code in chapter_computational_complexity * docs: Update code comment * style: update code order th same with java
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@ -14,6 +14,25 @@ function recur(n) {
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return n + res;
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}
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/* 递归转化为迭代 */
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function forLoopRecur(n) {
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// 使用一个显式的栈来模拟系统调用栈
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const stack = [];
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let res = 0;
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// 递:递归调用
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for (let i = 1; i <= n; i++) {
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// 通过“入栈操作”模拟“递”
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stack.push(i);
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}
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// 归:返回结果
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while (stack.length) {
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// 通过“出栈操作”模拟“归”
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res += stack.pop();
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}
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// res = 1+2+3+...+n
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return res;
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}
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/* 尾递归 */
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function tailRecur(n, res) {
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// 终止条件
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@ -39,8 +58,12 @@ let res;
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res = recur(n);
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console.log(`递归函数的求和结果 res = ${res}`);
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res = forLoopRecur(n);
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console.log(`递归转化为迭代的求和结果 res = ${res}`);
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res = tailRecur(n, 0);
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console.log(`尾递归函数的求和结果 res = ${res}`);
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res = fib(n);
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console.log(`斐波那契数列的第 ${n} 项为 ${res}`);
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@ -14,6 +14,25 @@ function recur(n: number): number {
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return n + res;
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}
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/* 递归转化为迭代 */
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function forLoopRecur(n: number): number {
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// 使用一个显式的栈来模拟系统调用栈
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const stack: number[] = [];
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let res: number = 0;
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// 递:递归调用
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for (let i = 1; i <= n; i++) {
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// 通过“入栈操作”模拟“递”
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stack.push(i);
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}
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// 归:返回结果
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while (stack.length) {
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// 通过“出栈操作”模拟“归”
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res += stack.pop();
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}
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// res = 1+2+3+...+n
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return res;
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}
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/* 尾递归 */
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function tailRecur(n: number, res: number): number {
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// 终止条件
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@ -39,6 +58,9 @@ let res: number;
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res = recur(n);
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console.log(`递归函数的求和结果 res = ${res}`);
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res = forLoopRecur(n);
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console.log(`递归转化为迭代的求和结果 res = ${res}`);
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res = tailRecur(n, 0);
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console.log(`尾递归函数的求和结果 res = ${res}`);
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